sebuah lapangan berbentuk lingkaran dengan diameter 56 m di sekeliling lapanngan akan dipasang lampu dengan jarak 4 m. berapakah banyak lampu yang diperlukan ?

y = 2 x − 1 y − in t erce pt ( x = 0 ) y = 2 ⋅ 0 − 1 = − 1 → ( 0 ; − 1 ) x − in t erce pt ( y = 0 ) 2 x − 1 = 0 2 x = 1 x = 0.5 → ( 0.5 ; 0 )

Answered by Anonymous | 2024-06-10

There are many ways to graph this equation. Here's one that you should be able to manage:
-- Pick any number at all for 'x'. [ y = 2x - 1 ], so double your number and subtract 1 to find 'y'. Mark a point on your graph at (x, y) .
-- Pick any different number at all for 'x'. [ y = 2x - 1 ], so double your number and subtract 1 to find 'y'. Mark a point on your graph at (x, y) .
-- Using your pencil and ruler, connect the two points that you have marked on your graph. Without moving the ruler, you may extend the line as far as you want in each direction.

Answered by AL2006 | 2024-06-10

To graph the equation y = 2 x − 1 , plot the y-intercept at (0, -1) and use the slope of 2 to find a second point at (1, 1). Connect these points with a straight line and label it with the equation. This creates your graphed line.
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Answered by Anonymous | 2024-12-24

DiketahuiDiameter : 56 mDikeliling dipasang lampu jarak 4 mDitanyaBanyak lampu yang diperlukanDijawabKeliling[tex] = \pi \times d = \frac{22}{ \cancel7} \times \cancel{ 56 } \: \: {}^{8} = 22 \times 8 = 176 {m}^{2} [/tex]Lampu yang dibutuhkan[tex] = \frac{176}{4} = 44[/tex]KesimpulanMaka butuh 44 lampu

Answered by aquila0152 | 2025-07-07