x 2 + 5 x − 300 = 0 Δ = b 2 − 4 a c = 5 2 − 4 ∗ 1 ∗ ( − 300 ) = 25 + 1200 = 1225 x 1 = 2 a − b − Δ = 2 − 5 − 1225 = 2 − 5 − 35 = − 2 − 40 = − 20 s i d e n o t c an a l so b e n e g a t i v e
x 2 = 2 a − b + Δ = 2 − 5 + 1225 = 2 − 5 + 35 = − 2 30 = 15 A n se w r : x = 15
The value of x that makes the triangle a right triangle is 15. By using the Pythagorean theorem, we derived a quadratic equation and solved for x . The negative root was discarded since side lengths cannot be negative.
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