15, 23, ...., 26,21,29
Answer (3)
C e n t er o f t h e c i rc l e i s t h e mi d p o in t A B w h ere A ( − 2 ; 4 ) & B ( 4 ; 2 ) ce n t er : O ( 2 − 2 + 4 ; 2 4 + 2 ) → O ( 1 ; 3 ) R a d i u s o f t h e c i rc l e i s d i s t an ce O t o A : r = ∣ O A ∣ = ( − 2 − 1 ) 2 + ( 4 − 3 ) 2 = 9 + 1 = 10 Eq u a t i o n o f a c i rc l e : ( x − a ) 2 + ( y − b ) 2 = r 2 w h e t e ce n t er i s ( a ; b ) an d r a d i u s i s r . Eq u a t i o n o f t hi s c i rc l e : ( x − 1 ) 2 + ( y − 3 ) 2 = ( 10 ) 2 ( x − 1 ) 2 + ( y − 3 ) 2 = 10
The equation of the circle with a diameter defined by the points (-2, 4) and (4, 2) can be found by calculating the midpoint to find the center, which is (1, 3), and the radius, which is 10 . Therefore, the equation of the circle in standard form is ( x − 1 ) 2 + ( y − 3 ) 2 = 10 .
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Jawaban:15, 23, 18, 26, 21, 29Penjelasan dengan langkah-langkah:23 ke 26 itu ditambah 326 ke 29 juga ditambah 3lalu untuk titik titik nya itu, 15 ditambah berapa supaya hasilnya 21? dengan ditambah 3.jadi 15 + 3 itu 18 lalu 18 + 3 hasil nya 21.
