x 2 + 3 x − 18 = 0 a = 1 ; b = 3 ; c = − 18 Δ = b 2 − 4 a c → Δ = 3 2 − 4 ⋅ 1 ⋅ ( − 18 ) = 9 + 72 = 81 x 1 = 2 a − b − Δ ; x 2 = 2 a − b + Δ Δ = 81 = 9 x 1 = 2 ⋅ 1 − 3 − 9 = 2 − 12 = − 6 ; x 2 = 2 ⋅ 1 − 3 + 9 = 2 6 = 3
x+6 and x-3 in which the absolute value would be if a positive 3 and a negative 6
The quadratic equation x 2 + 3 x − 18 = 0 can be solved using the quadratic formula, yielding the solutions x = − 6 and x = 3 . First, we identify the coefficients and calculate the discriminant, then apply the quadratic formula to find the roots. Thus, the solution reveals two distinct values for x .
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Jawaban:Tandus, Gersang, Mandul