HotelInfantesAgres - Tempat Tanya Jawab Pelajaran & Ilmu Pengetahuan Logo

In Matematika / Sekolah Menengah Atas | 2025-07-03

jika skala denah yang digunakan 1 : 300. luas gedung sebenarnya adalah

Asked by laurenza1994

Answer (4)

use what they tell you to create the equations
a=33+2b & 57=3b-a
for this to work we need to substitute a variable to get rid of it. look at 57=3b-a (lets switch it around s that the equation reads "a=") 57+a=3b a=3b-57 (this is our new equations)
so now we know that a=33+2b & a=3b-57 so we can write 33+2b=3b-57. we have now "gotten rid" of "a"
SOLVE FOR B
33+2b=3b-57 (get variable alone) 33= 3b-2b-57 (subtract and add accordingly) 33= b-57 33+57=b 90=b (this means that movie b is 90 long)
SOLVE FOR A
you can plug "b" into any of the original equations.
a=33+2b a=33+2(90) a=33+180 a=213
CHECK
plug "a" into any of the original equations to find "b" if b=90 then you know you've done it right
213=33+2b 213-33=2b 180=2b 180/2=b 90=b
hope this helps :)

Answered by secretlyblu | 2024-06-10

X is the running time for movie A and y the running time for movie B X = 2y + 33 3y - × = 57 x- 2y = 33 -× + 3y = 57 => y = 90 => x 33 + 180 = 213

Answered by pepe11 | 2024-06-10

The running time for movie A is 213 minutes, and for movie B, it is 90 minutes. This is found by solving the equations that relate their running times based on the conditions provided. By substituting the values, we confirm the relationships hold true.
;

Answered by secretlyblu | 2024-12-26

Jawaban:1 cm dalam gambar denah merupakan 300 cm dalam kehidupan nyata

Answered by vlncahndarsta | 2025-07-04