idhgam mimi di surat al baqarah

0\ \ \ and\ \ \ b>0\\ ----------------------------- \\log(5x)+log(x-1)=2\ \ \ \Rightarrow\ \ \ D:\ 5x>0\ \ \ and\ \ \ x-1>0\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x>0\ \ \ and\ \ \ \ \ \ \ \ x>1\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=(1;+\infty)\\\\log[5x\cdot(x-1)]=2\ \ \ \Leftrightarrow\ \ \ 5x(x-1)=10^2"> l o g p ​ a = b ⇔ p b = a l o g a + l o g b = l o g ( a ⋅ b ) ⇒ D : a > 0 an d b > 0 − − − − − − − − − − − − − − − − − − − − − − − − − − − − − l o g ( 5 x ) + l o g ( x − 1 ) = 2 ⇒ D : 5 x > 0 an d x − 1 > 0 . x > 0 an d x > 1 . D = ( 1 ; + ∞ ) l o g [ 5 x ⋅ ( x − 1 )] = 2 ⇔ 5 x ( x − 1 ) = 1 0 2
5 x 2 − 5 x = 100 / : 5 x 2 − x − 20 = 0 x 2 − 5 x + 4 x − 20 = 0 x ( x − 5 ) + 4 ( x − 5 ) = 0 ( x − 5 ) ( x + 4 ) = 0 ⇔ x − 5 = 0 or x + 4 = 0 . x = 5 or x = − 4 5 ∈ D ; − 4 ∈ / D A n s . x = 5

Answered by kate200468 | 2024-06-10

0 \wedge x-1>0\\ D:x>0 \wedge x>1\\ D:x>1\\ \log5x(x-1)=2\\ 10^2=5x^2-5x\\ 5x^2-5x-100=0\\ x^2-x-20=0\\ x^2-5x+4x-20=0\\ x(x-5)+4(x-5)=0\\ (x+4)(x-5)=0\\ x=-4 \vee x=5\\ -4\not \in D\Rightarrow x=5"> lo g 5 x + lo g ( x − 1 ) = 2 D : 5 x > 0 ∧ x − 1 > 0 D : x > 0 ∧ x > 1 D : x > 1 lo g 5 x ( x − 1 ) = 2 1 0 2 = 5 x 2 − 5 x 5 x 2 − 5 x − 100 = 0 x 2 − x − 20 = 0 x 2 − 5 x + 4 x − 20 = 0 x ( x − 5 ) + 4 ( x − 5 ) = 0 ( x + 4 ) ( x − 5 ) = 0 x = − 4 ∨ x = 5 − 4  ∈ D ⇒ x = 5

Answered by konrad509 | 2024-06-10

To solve logarithmic equations, first understand the properties of logarithms. Combine logarithms using properties like the product property and then convert the equation to its exponential form. Solve for the variable, ensuring all logarithmic values are positive for valid solutions.
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Answered by kate200468 | 2024-12-24

Jawaban:ayat 19 pada lafadz اٰذَانِهِمْ مِّنَkarena idgham Mimi merupakan mim sukun/ mim mati bertemu dengan huruf mim

Answered by iklilputrisantoso | 2025-07-05