l o g 2 + l o gx = 1 ; D : x ∈ R + l o g ( 2 ⋅ x ) = l o g 10 ⟺ 2 x = 10 / : 2 x = 5 ∈ D S o l u t i o n : x = 5.
0\\ \log2x=1\\ 10^1=2x\\ 2x=10\\ x=5"> lo g 2 + lo g x = 1 D : x > 0 lo g 2 x = 1 1 0 1 = 2 x 2 x = 10 x = 5
The solution to the equation lo g 2 + lo g x = 1 is x = 5 . We combined the logarithms using the property of logarithms and simplified to find the value. The final result is x = 5 .
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