fungsi penawaran P=Q²+9Q+18 dan gambar diagram nya tolong di bantu ya urgent plis

R= A p L ​
R-resistance p-resistivity [Ohm m] A-cross sectional area L-length R=20 Ohm l=2m A= π r 2 = π ( 0 , 01 ) 2 = 0 , 000314 c m 2 =0,314 1 0 − 7 m² p= L R ∗ A ​ p= 2 20 ∗ 0 , 314 ∗ 1 0 − 7 ​ =0,000000314 Ohm*m

Answered by luana | 2024-06-10

The resistivity of the material in the wire is approximately 7.85 x 10^-8 ohm-meters. This was calculated using the formula for resistance, taking into account the wire's length and cross-sectional area. The calculations show that the resistivity value is typical for conductive materials.
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Answered by luana | 2024-10-01

Jawab:Q= -3 / Q= -6Penjelasan dengan langkah-langkah:[tex]P=Q^{2} +9Q + 18[/tex][tex]0=(Q + 3)(Q + 6)[/tex]

Answered by Sunariyadi | 2025-07-05