diketahui barisan bilangan 1,3,5,7,9....nilai dari suku ke 15 adalah

I have not done this in advance. I'm just going to write it down and see what I can do with it:
[ 1/(x+3)² - 1/x² ] / 3
Multiply the top and bottom by (x+3)² :
[ 1 - (x+3)²/x² ] / 3 (x+3)²
Multiply the top and bottom by x² :
[ x² - (x+3)² ] / 3 x² (x+3)²
Now it's just a matter of expanding and cleaning things up, and hope and pray that a lot of things cancel.
Eliminate the parentheses on top and bottom:
[ x² - x² - 6x -9 ] / 3 x² (x² + 6x + 9)
Combine the x² terms on top, and divide top and bottom by 3 :
[ - 2x - 3 ] / x² (x² + 6x + 9)
Finally, all I can make of this is:
- (2x + 3) / [ x(x+3) ]² .
That's not a whole lot prettier than the original form, but at least we got rid of those fractions in the numerator of a fraction.
I hope this is some help to you.

Answered by AL2006 | 2024-06-10

3 ( x + 3 ) 2 1 ​ − x 2 1 ​ ​ = 3 ( x + 3 ) 2 1 ​ − 3 x 2 1 ​ = 3 x 2 ( x + 3 ) 2 x 2 ​ − 3 x 2 ( x + 3 ) 2 ( x + 3 ) 2 ​ = 3 x 3 ( x + 3 ) 2 x 2 − x 2 − 6 x − 9 ​ = 3 x 2 ( x + 3 ) 2 − 6 x − 9 ​ = 3 x 2 ( x + 3 ) 2 3 ( − 2 x − 3 ) ​ = − x 2 ( x + 3 ) 2 2 x + 3 ​

Answered by Anonymous | 2024-06-10

The expression 3 ( x + 3 ) 2 1 ​ − x 2 1 ​ ​ simplifies to ( x + 3 ) 2 x 2 − ( 2 x + 3 ) ​ after combining fractions and expanding the numerator. This process includes finding a common denominator, simplifying, and factoring. Following these steps allows us to better manage complex fractions in the numerator.
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Answered by AL2006 | 2024-12-26

Jawaban:29Penjelasan dengan langkah-langkah:Un bilangan ganjil adalah 2n - 1Un = 2n - 1U15 = 2(15) - 1U15 = 30 - 1U15 = 29[tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]

Answered by Milana01 | 2025-07-03