hasil dari 4x^2yz^2/5 * 2/7xy : 5yz/14 p.s ^ = pangkat * = kali

( x 3 − x 2 + x − 1 ) ( x 2 − 1 )
x 5 − x 3 − x 4 + x 2 + x 3 − x − x 2 + 1
x 5 − x 4 − x + 1
x 4 ( x − 1 ) − ( x − 1 )
( x 4 − 1 ) ( x − 1 )

Answered by iloveonedirection | 2024-06-24

The least common multiple of the polynomials x 3 − x 2 + x − 1 and x 2 − 1 can be found by factoring both, resulting in ( x − 1 ) ( x + 1 ) ( x 2 + 1 ) . While the best match from the choices provided was not listed, the derived LCM is valid. Therefore, the answer matches the polynomial processed correctly through factorization principles.
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Answered by iloveonedirection | 2025-06-12

Jawab:Penjelasan dengan langkah-langkah:The result of the expression (4x²yz² / 5) * (2/7xy) : (5yz / 14) is (16x³z³)/(25y).Here's how to solve it:First, multiply the two fractions:(4x²yz² / 5) * (2/7xy) = (4x²yz² * 2) / (5 * 7xy) = (8x³y²z²) / (35xy)Now, divide the result by (5yz / 14):((8x³y²z²) / (35xy)) : (5yz / 14) = ((8x³y²z²) / (35xy)) * (14 / (5yz))Multiply the fractions:((8x³y²z² * 14) / (35xy * 5yz)) = (112x³y²z²) / (175xy²z)Simplify the expression by dividing both the numerator and denominator by their common factors:(112x³y²z²) / (175xy²z) = (16x³z³) / (25y)

Answered by hotelpoornaveg | 2025-07-07