Bentuk sederhana dari 3log81 + 3log9 + 3log27
Answer (5)
OK"> y = 3 x x = 25 y = 75 75 = 3 ∗ 25 75 = 75 − > O K
"Yes" the point (25, 75) lie on the straight line y=3x
The equation f of straight line is y = mx + c
where m is slope of line and c is intercept
Given straight equation is
y = 3x.....(1)
If we compare this equation with straight line equation. we get,
m = 3 and 0 is intercept,
Given point are (25, 75).
put these given point in equation (1)
75 = 3 (25).
75 = 75.
Therefore, the given** statement **is true.
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The point (25, 75) lies on the line given by the equation y = 3 x because substituting x = 25 into the equation results in y = 75, which matches the y-coordinate of the point. Therefore, the point satisfies the equation of the line.
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•°• Bentuk sederhana dari [tex]\sf{³log(81) + ³log(9) + ³log(27)}[/tex] adalah [tex]\underline{\boxed{\red{\sf{9}}}}[/tex].[tex] \\ \\ [/tex]Penjelasan dengan langkah-langkah:[tex]\sf{³log(81) + ³log(9) + ³log(27)}[/tex]= [tex]\sf{³log(81 × 9 × 27)}[/tex]= [tex]\sf{³log(3⁴ × 3² × 3³)}[/tex]= [tex]\sf{³log(3^{(4 + 2 + 3)})}[/tex]= [tex]\sf{³log(3^{(6 + 3)})}[/tex]= [tex]\sf{³log(3⁹)}[/tex]= [tex]\sf{9 × \cancel{\red{³log(3)}}¹}[/tex]= [tex]\sf{9 × 1}[/tex]= [tex]\underline{\boxed{\red{\sf{9}}}}[/tex][tex]~[/tex][tex]__________________________________________________________________________________________[/tex][tex] \\ \\ [/tex] [tex]\blue{\boxed{\colorbox{skyblue}{\rm{- AvR}}}}[/tex]
Jawaban:9Penjelasan dengan langkah-langkah:[tex] \tt = {}^{3} log(81) + {}^{3} log(9) + {}^{3} log(27) [/tex][tex] \tt = {}^{3} log( {3}^{4} ) + {}^{3} log( {3}^{2} ) + {}^{3} log( {3}^{3} ) [/tex]= 4 + 2 + 3= 9[tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]
