v_b-the\ speed\ of\ the\ boat\\v_c-the\ speed\ of\ the\ current\\\\v_b+v_c=\frac{210}{10}=21\ (mph)\\\\v_b-v_c=\frac{210}{70}=3\ (mph)\\\\ +\left\{\begin{array}{ccc}v_b+v_c=21\\v_b-v_c=3\end{array}\right\\-----------\\.\ \ \ \ \ \ 2v_b=24\ \ \ \ /:2\\.\ \ \ \ \ \ \ \ \ v_b=12\ (mph)\\\\12+v_c=21\\v_c=21-12\\v_c=9\ (mph)
A n s w er : t h e s p ee d o f t h e b o t h i s 12 m p h t h e s p ee d o f t h e c u rre n t i s 9 m p h
The speed of the boat in still water is 12 mph, and the speed of the current is 9 mph. This was found using a system of equations based on the given travel times and distances. By setting up equations for downstream and upstream travel and solving them, we determined the speeds accurately.
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Jawab:Penjelasan dengan langkah-langkah:Jawaban: B. 125.249. Penjelasan dengan langkah-langkah: Untuk memudahkan, mari kita pisah angka 6 dan angka 2. Karena yang diminta adalah ...