Saya membeli 3 butir telur dengan harga Rp 15 - sebutirnya dan 1kg gula seharga Rp 120 nerapa uang kembalian jika uang saya 1.000

1. x 2 − 169 = 0 x 2 − 1 3 2 = 0 ( x − 13 ) ( x + 13 ) = 0 ⟺ x = 13 ∨ x = − 13
2. x 2 + 14 x + 49 = 0 x 2 + 2 x ⋅ 7 + 7 2 = 0 ( x + 7 ) 2 = 0 ( x + 7 ) ( x + 7 ) = 0 ⟺ x = − 7
3. x 2 − 17 x + 42 = 0 x 2 − 14 x − 3 x + 42 = 0 x ( x − 14 ) − 3 ( x − 14 ) = 0 ( x − 14 ) ( x − 3 ) = 0 ⟺ x = 14 ∨ x = 3
4. 2 x 2 − 9 x − 5 = 0 2 x 2 − 10 x + x − 5 = 0 2 x ( x − 5 ) + 1 ( x − 5 ) = 0 ( x − 5 ) ( 2 x + 1 ) = 0 \iffx = 5 ∨ x = − 2 1 ​
5. 3 x 2 + 11 x − 4 = 0 3 x 2 + 12 x − x − 4 = 0 3 x ( x + 4 ) − 1 ( x + 4 ) = 0 ( x + 4 ) ( 3 x − 1 ) = 0 ⟺ x = − 4 ∨ x = 3 1 ​
6. t hi s s am e l ik e 1. x 2 − 196 = 0 x 2 − 1 4 2 = 0 ( x − 14 ) ( x + 14 ) = 0 ⟺ x = 14 ∨ x = − 14

Answered by Anonymous | 2024-06-10

The equations can be factored and their zeros found through various methods depending on the structure of the equation, including factoring by grouping, recognizing perfect squares, and utilizing the difference of squares formula. The zeros found are as follows: 13, -13; -7; 14, 3; 5, -1/2; -4, 1/3. The set of zeros includes repeated factors depending on the equation.
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Answered by Anonymous | 2025-02-04

Jawaban:Rp.835Penjelasan dengan langkah-langkah:Diket:harga telur 1 butir = Rp. 15harga gula 1 kg = Rp 120uang = Rp. 1000Dit: Berapa uang kembaliannyajawab:3 butir telur = Rp 15 ×3 = Rp. 451 kg gula = Rp 120total belanja = Rp 45 + Rp 120 = Rp 165uang kembalian = Rp. 1000 - Rp. 165 = Rp. 835jadi uang kembaliannya adalah Rp 835

Answered by arianisadewi4 | 2025-07-04