3) Diketahui barisan geometri: 7, 14, 28, 56, Tentukanlah nilai suku ke 11 (nilai U₁₁)!

b 2 − 5 b − 24 = 0 a = 1 , b = − 5 , c = − 24 Δ = b 2 − 4 a c = ( − 5 ) 2 − 4 ⋅ 1 ⋅ ( − 24 ) = 25 + 96 = 121 x 1 ​ = 2 a − b − Δ ​ ​ = 2 5 − 121 ​ ​ = 2 5 − 11 ​ = 2 − 6 ​ = − 3
x 2 ​ = 2 a − b + Δ ​ ​ = 2 5 + 121 ​ ​ = 2 5 + 11 ​ = 2 16 ​ = 8 A n s w er : x = − 3 or x = 8

Answered by Lilith | 2024-06-10

b 2 − 5 b − 24 = 0 b 2 − 8 b + 3 b − 24 = 0 b ( b − 8 ) + 3 ( b − 8 ) = 0 ( b + 3 ) ( b − 8 ) = 0 b = − 3 ∨ b = 8

Answered by konrad509 | 2024-06-10

To solve the equation b 2 − 5 b − 24 = 0 , we use the quadratic formula. The solutions are b = − 3 and b = 8 .
;

Answered by Lilith | 2024-12-24

7, 14, 28, 56, ...a = 7r = 14/7 = 2Suku ke 11[tex] u_{n} = a {r}^{n - 1} [/tex][tex] u_{7} = 7 \times {2}^{11 - 1} [/tex][tex] u_{7} = 7 \times {2}^{10} [/tex][tex] u_{7} = 7 \times 1.024[/tex]U7 = 7.168[tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]

Answered by Milana01 | 2025-07-03