11. Pada segitiga sama kaki PQR, diketahui PQ = PR = 17cm. Jika kelilingnya adalah 50cm, maka luasnya adalah?
Answer (4)
ZnS + O --> ZnO + SO
Okay so first you have to count up the number of elements on each side of the equation. Your objective is to have the same number of each element on both sides.
Left Side: Zn - 1 S - 1 O - 1
Right Side: Zn - 1 S - 1 O - 2
Since there are two oxygens on the right side, you have to add a coefficient of 2 to the oxygen on the left side. The coefficient tells us that that element or molecule is being multiplied by the value of coefficient. Since we're adding a coefficient of 2 to the oxygen on the left side, there are now 2 oxygens on that side. Because that is the same amount of oxygen as on the right, the equation is now balanced.
Your final equation should look like this: ZnS + 2 O --> ZnO + SO
In conclusion, the answer is 2 .
there has to be the same amount of each element on both sides of the equation
ZnS+ O => Zn O + S O 1 Zn, 1 S, 1O 1 Zn, 1 S, 2O
ZnS +** 2O **=> ZnO + SO
The chemical equation Z n S + O 2 → Z n O + S O 2 is balanced with a coefficient of 3 in front of O 2 . This ensures that the number of oxygen atoms is equal on both sides. Therefore, the answer is C. 3 .
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Panjang alas= K - (PQ + PR) = 50 - (17 + 17) cm= 50 - 34 cm= 16 cmTinggi[tex] = \sqrt{ {17}^{2} - {(16 \div 2)}^{2} } [/tex][tex] = \sqrt{289 - {8}^{2} } [/tex][tex] = \sqrt{289 - 64} [/tex][tex] = \sqrt{225} [/tex]= 15 cmLuas= ½ × alas × tinggi= ½ × 16 cm × 15 cm[tex] = \frac{240}{2} [/tex]= 120 cm²[tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]
