4 0,375 ; ; 75%; 0,6 Urutkan dari kecil ke besar! 5​spasi 4/5

X = t² - 5.2t + 1.2
At time 3.4s . . . X = (3.4)² - (5.2)(3.4) + 1.2 = -4.92m
At time 4.5s . . . X = (4.5)² - (5.2)(4.5) + 1.2 = -1.95m
The ** displacement **over that interval is (-1.95m) - (-4.92m) = +2.97m
Average velocity = (displacement) / (time for the displacement) in the direction of the displacement.
Time interval = (4.5s - 3.4s) = 1.1 second
Average velocity = 2.97m / 1.1s = 2.7 m/s in the direction of the displacement .

Answered by AL2006 | 2024-06-10

The question asks for the displacement and average velocity of a particle in a certain time interval in a high school Physics context. By using the position-time equation and calculating differences in position, the displacement and average velocity can be determined. ;

Answered by muskangoswami8788 | 2024-06-24

The displacement of the particle during the time interval from 3.4 s to 4.5 s is approximately -0.000602 m. The average velocity over this interval is approximately -0.000548 m/s, indicating it's moving in the opposite direction. Hence, the motion is in a negative directional change during this time period.
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Answered by AL2006 | 2025-02-19

Jawaban:0,375 ; 0,6 ; 75%Penjelasan dengan langkah-langkah:supaya lebih gampang melihat yg lebih kecil, ubah semuanya ke desimal saja.0,375 sudah desimal0,6 sudah desimal75% diubah ke desimal adalah 0,75lalu tinggal diurutkan saja angka setelah komanya dari kecil ke besar.semoga membantu

Answered by belulu | 2025-07-03

Ubah semua ke bentuk desimal:4 = 4,000,375 = 0,37575% = 0,750,6 = 0,64/5 = 0,8--- Urutan dari kecil ke besar: 0,375 0,6 75% 4/5 4--- Jawaban akhir:0,375 0,6 75% 4/5 4

Answered by EhanTITL | 2025-07-03