f ( x ) = x 2 − 1 g ( x ) = x 2 + 2 f ( g ( x )) = ( x 2 + 2 ) 2 − 1 = x 4 + 4 x 2 + 4 − 1 = x 4 + 4 x 2 + 3 x 4 + 4 x 2 + 3 = x 4 + x 2 + 3 x 2 + 3 = x 2 ( x 2 + 1 ) + 3 ( x 2 + 1 ) = ( x 2 + 3 ) ( x 2 + 1 )
To find f ( g ( x )) , we substitute g ( x ) into f and expand, resulting in x 4 + 4 x 2 + 3 . This expression can be factored as ( x 2 + 3 ) ( x 2 + 1 ) .
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Jawaban:hopefully stay alive smgt!