What is the solution set for the quadratic equation \(x^2 - 16 = 0\)?

x 2 − 16 = 0 ( x − 4 ) ( x + 4 ) = 0 #1 x + 4 = 0 x = − 4 ​ #2 x − 4 = 0 x = 4 ​ S = { − 4 ; 4 } ​ ​

Answered by mariamikayla | 2024-06-10

x is either 4 or -4 because it is the square root of 16

Answered by mathdragon | 2024-06-10

The solution set for the quadratic equation x 2 − 16 = 0 is { -4, 4 }. This is obtained by first rewriting the equation as x 2 = 16 and then taking the square root of both sides. Thus, we find two solutions: x = 4 and x = − 4 .
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Answered by mariamikayla | 2024-12-26