how? I'm so lost, alsphfbnslq
Answer (1)
0\\ D:x>1\\ \log_3(x-1)=2\\ 3^2=x-1\\ 9=x-1\\ x=10"> D : x − 1 > 0 D : x > 1 lo g 3 ( x − 1 ) = 2 3 2 = x − 1 9 = x − 1 x = 10
0\\ D:x>1\\ \log_3(x-1)=2\\ 3^2=x-1\\ 9=x-1\\ x=10"> D : x − 1 > 0 D : x > 1 lo g 3 ( x − 1 ) = 2 3 2 = x − 1 9 = x − 1 x = 10
